como factorizar (x^3+2x^2-5x-6)/(x^3-7x+6)

Question

Count Iblis · Answer

http://en.wikipedia.org/wiki/Rational_root_theorem

http://es.wikipedia.org/wiki/Teorema_de_la_raíz_racional


You find that 

x = -1, x = 2 and x = -3 are roots of x^3+2x^2-5x-6, therefore:

x^3+2x^2-5x-6 = (x+1)(x-2)(x+3)


x = 1, x = 2 and x=-3 are roots of x^3-7x+6, therefore:

x^3-7x+6 = (x-1)(x-2)(x+3)

matematicas · Answer

how would you do it without synthetic div. can you factor it like a quadratic